2x^2=360000

Solution for 2x^2=360000 equation:

2x^2=360000

We move all terms to the left:

2x^2-(360000)=0

a = 2; b = 0; c = -360000;
Δ = b2-4ac
Δ = 02-4·2·(-360000)
Δ = 2880000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2880000}=\sqrt{1440000*2}=\sqrt{1440000}*\sqrt{2}=1200\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1200\sqrt{2}}{2*2}=\frac{0-1200\sqrt{2}}{4}
=-\frac{1200\sqrt{2}}{4}
=-300\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1200\sqrt{2}}{2*2}=\frac{0+1200\sqrt{2}}{4}
=\frac{1200\sqrt{2}}{4}
=300\sqrt{2}
$